2[p-(4p+13)+11]=2(p+2)

Solution for 2[p-(4p+13)+11]=2(p+2) equation:

Simplifying
2[p + -1(4p + 13) + 11] = 2(p + 2)

Reorder the terms:
2[p + -1(13 + 4p) + 11] = 2(p + 2)
2[p + (13 * -1 + 4p * -1) + 11] = 2(p + 2)
2[p + (-13 + -4p) + 11] = 2(p + 2)

Reorder the terms:
2[-13 + 11 + p + -4p] = 2(p + 2)

Combine like terms: -13 + 11 = -2
2[-2 + p + -4p] = 2(p + 2)

Combine like terms: p + -4p = -3p
2[-2 + -3p] = 2(p + 2)
[-2 * 2 + -3p * 2] = 2(p + 2)
[-4 + -6p] = 2(p + 2)

Reorder the terms:
-4 + -6p = 2(2 + p)
-4 + -6p = (2 * 2 + p * 2)
-4 + -6p = (4 + 2p)

Solving
-4 + -6p = 4 + 2p

Solving for variable 'p'.

Move all terms containing p to the left, all other terms to the right.

Add '-2p' to each side of the equation.
-4 + -6p + -2p = 4 + 2p + -2p

Combine like terms: -6p + -2p = -8p
-4 + -8p = 4 + 2p + -2p

Combine like terms: 2p + -2p = 0
-4 + -8p = 4 + 0
-4 + -8p = 4

Add '4' to each side of the equation.
-4 + 4 + -8p = 4 + 4

Combine like terms: -4 + 4 = 0
0 + -8p = 4 + 4
-8p = 4 + 4

Combine like terms: 4 + 4 = 8
-8p = 8

Divide each side by '-8'.
p = -1

Simplifying
p = -1